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Question: Which of the following order of energies of molecular or bitals of \(N_{2}\)is correct?...

Which of the following order of energies of molecular or bitals of N2N_{2}is correct?

A

(π2py)<(σ2pz)<(π2px)(π2py)(\pi 2p_{y}) < (\sigma 2p_{z}) < (\pi*2p_{x}) \approx (\pi*2p_{y})

B

(π2py)>(σ2pz)>(π2px)(π2Py)(\pi 2p_{y}) > (\sigma 2p_{z}) > (\pi*2p_{x}) \approx (\pi*2P_{y})

C

(π2Py)<(σ2Pz)>(π2px)(π2Py)(\pi 2P_{y}) < (\sigma 2P_{z}) > (\pi*2p_{x}) \approx (\pi*2P_{y})

D

(π2py)>(σ2Pz)<(π2px)(π2Py)(\pi 2p_{y}) > (\sigma 2P_{z}) < (\pi*2p_{x}) \approx (\pi*2P_{y})

Answer

(π2py)<(σ2pz)<(π2px)(π2py)(\pi 2p_{y}) < (\sigma 2p_{z}) < (\pi*2p_{x}) \approx (\pi*2p_{y})

Explanation

Solution

: For molecules such as B2,C2N2B_{2},C_{2}N_{2}etc. The increasing order of energies of various molecular orbitals is

σ1s<σ1s<σ2s<σ2s<(π2px=π2py)<σ2pz<σ2pz\sigma 1s < \sigma*1s < \sigma 2s < \sigma*2s < (\pi 2p_{x} = \pi 2py) < \sigma 2p_{z} < \sigma*2p_{z}