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Question

Chemistry Question on Chemical bonding and molecular structure

Which of the following is the correct order of stability for the given superoxides?

A

KO2<RbO2<CsO2\text{KO}_2 < \text{RbO}_2 < \text{CsO}_2

B

CsO2<RbO2<KO2\text{CsO}_2 < \text{RbO}_2 < \text{KO}_2

C

RbO2<CsO2<KO2\text{RbO}_2 < \text{CsO}_2 < \text{KO}_2

D

KO2<CsO2<RbO2\text{KO}_2 < \text{CsO}_2 < \text{RbO}_2

Answer

KO2<RbO2<CsO2\text{KO}_2 < \text{RbO}_2 < \text{CsO}_2

Explanation

Solution

The correct option is (A): KO2<RbO2<CsO2\text{KO}_2 < \text{RbO}_2 < \text{CsO}_2