Question

Which of the following is soluble in water?
(A) $C{S_2}$
(B) ${C_2}{H_5}OH$
(C) $CC{l_4}$
(D) $CHC{l_3}$

Answer 1

Initially you should know that for the process of solubility both the solvent must be of the same category. This means polarity of both the substances must match with each other. Water is a polar molecule.

Complete step by step solution:
As you know that water is a polar solvent. Therefore, the other solvent must be a polar solvent so that it can easily dissolve in the medium.
Polarity plays a major role in the solubility factor. Polar substances are soluble in water while non-polar substances are soluble in oils and fats.
The use of like dissolves like rule is done by Covalent solubility. This means that substances with the same type of polarity will be soluble in one another. Moreover, compounds with different polarities will be insoluble in one another.
Checking the polarity of two materials is so easy. Simply mix the liquid with an equal part of water in a test tube and allow the mixture to sit and get stable. Examine the mixture after a few minutes, the liquids have sat together for a time.
If they have not separated, but have formed a solution, the unknown liquid is polar. If there is a clear boundary between the two liquids, it is non-polar.
Here $C_2H_5OH$ is a polar solvent.
Therefore, it is easily soluble in water. So, option B is the correct option.

Note:
Carbon disulphide is also called Carbon Bisulfide, a colourless, toxic, highly volatile and flammable liquid chemical compound. Carbon tetrachloride is used for dry cleaning, degreasing metals, fumigating, manufacturing refrigerants and aerosol propellants, and is also used in fire extinguishers. Chloroform is an organic compound. It is a colourless, strong-smelling, dense liquid.