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Chemistry Question on Haloalkanes and Haloarenes

Which of the following is optically active?

A

CH3−CH∣O∣H−CH∣O∣H−CH3CH_3 - \underset{\overset{|}{O}H}{\overset{\underset{|}{H}}{C}} -\underset{\overset{|}{O}H}{\overset{\underset{|}{H}}{C}}-CH_3

B

CH3−CHOH−CH3C{{H}_{3}}-CHOH-C{{H}_{3}}

C

CH3−CO∣∣−CB∣rB∣r−COOHCH_3 - \underset{\overset{||}{O}}{C}- \underset{\overset{|}{B}r}{\overset{\underset{|}{B}r}{C}}-COOH

D

CH3−CH2−CO∣H=OCH_3 - CH_2 - \underset{\overset{|}{O}H}{C} = O

Answer

CH3−CH∣O∣H−CH∣O∣H−CH3CH_3 - \underset{\overset{|}{O}H}{\overset{\underset{|}{H}}{C}} -\underset{\overset{|}{O}H}{\overset{\underset{|}{H}}{C}}-CH_3

Explanation

Solution

Optically active compounds have at least one asymmetric or chiral carbon atom. Compound given in option [a] contains two chiral carbon atoms as CH3−CH∗∣O∣H−CH∗∣O∣H−CH3CH_3 - \underset{\overset{|}{O}H}{\overset{\underset{*|}{H}}{C}}- \underset{\overset{|}{O}H}{\overset{\underset{*|}{H}}{C}}-CH_3 ∴\therefore it is optically active.