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Question

Question: Which of the following is not correct? A) \(\left| z \right| \geqslant 0\) B) \(\left| z \right|...

Which of the following is not correct?
A) z0\left| z \right| \geqslant 0
B) zRe(z)\left| z \right| \geqslant \operatorname{Re} (z)
C) xIm(z)\left| x \right| \geqslant \operatorname{Im} (z)
D) zz=z3z\overline z = {\left| z \right|^{ - 3}}

Explanation

Solution

According to the question we have to choose the option which is not correct.
So, first of all we have to check each option to determine that it is correct or not but as given in the options Z is a complex number which is (a+ib)(a + ib) where a, and b are the real numbers and i is the imaginary term. Now, we have determined the option is correct or not by checking each term of the options.
As given in the as we know that the value of z is (a+ib)(a + ib) so, the value of z\overline z is (aib)(a - ib) which is the inverse of z.

Complete step-by-step answer:
Step 1: First of all we have to determine the option (A) which is z0\left| z \right| \geqslant 0
As we know that z = (a+ib)(a + ib)
Hence,
(a+ib)0\left| {(a + ib)} \right| \geqslant 0 which is true because by placing values of a, and b which are real numbers the value obtained will always be greater than or equal to zero.
Step 2: Now, we have to determine the option (B) which is zRe(z)\left| z \right| \geqslant \operatorname{Re} (z) so, for every real z as given in the question (a+ib)>Re(a+ib)\left| {(a + ib)} \right| > \operatorname{Re} (a + ib) which is true because for all the negative values of z, z\left| z \right| will always be positive.
Step 3: Now, we have to determine the option (C) which is xIm(z)\left| x \right| \geqslant \operatorname{Im} (z) which is definitely true because given that z is an imaginary term.
Step 4: Now, same as the previous steps we will determine the option (D) which is zz=z3z\overline z = {\left| z \right|^{ - 3}} so, as mentioned in the solution hint that the value of z is (a+ib)(a + ib) so, the value of z\overline z is (aib)(a - ib) which is the inverse of z.
Hence on solving the L.H.S. which is zzz\overline z by placing the values of z and z\overline z
=(a+ib)(aib) =a2(ib)2 =a2i2b2  = (a + ib)(a - ib) \\\ = {a^2} - {(ib)^2} \\\ = {a^2} - {i^2}{b^2} \\\
Step 5: Now, on substituting the value of i which is -1 in the expression obtained in the step 4.
=a2+b2= {a^2} + {b^2}
Which is not equal to z3{\left| z \right|^{ - 3}}

Hence, by solving all the options we have obtained the correct option which is (A) z0\left| z \right| \geqslant 0

Note: As mentioned in the question z is a complex number which is equal to (a+ib)(a + ib) and the value of z\overline z is (aib)(a - ib) which is the inverse of z.
On multiplying the imaginary term i with i we will obtain i2{i^2} and the value of i2{i^2} is equal to 1.