Question

Which of the following is isoelectronic and isostructural with $C{{O}_{2}}$?
a.) $N{{O}_{2}}$
b.) $N{{O}_{3}}^{-}$
c.) $N{{O}_{2}}^{-}$
d.) ${{N}_{2}}O$

Answer 1

To answer the given question, we must first remember the terms isoelectronic and isostructural. Then we can compare the options with $C{{O}_{2}}$ as isoelectronic and isostructural.

_Complete step by step solution: _
Isoelectronic refers to two atoms, ions, or molecules that have the same electronic structure and the same number of valence electrons.
Two crystals are said to be isostructural, if they have the same structure, but not necessarily the same cell dimensions nor the same chemical composition, and with a comparable variability in the atomic coordinates to that of the cell dimensions and chemical composition.
To find the isoelectronic and isostructural isomer of $C{{O}_{2}}$we need to find the which among the mentioned compounds have the same number of electrons as $C{{O}_{2}}$.
In $C{{O}_{2}}$we have to find out the number of electrons.
In carbon or C there are 6 electrons (since atomic number is 6) and that of oxygen or O is 8. Since there are 2 atoms it will be 16.

So, the total number of electrons in $C{{O}_{2}}$becomes 6 + 8 = 22.
In case of $N{{O}_{2}}$, the total number of electrons will be = 7 (since atomic number of N is 7) + 16 = 23 electrons.
In case of $N{{O}_{3}}^{-}$, the total number of electrons will be 7 + 24 + 1 (due to the presence of the extra charge) = 32 electrons.
In the case of $N{{O}_{2}}^{-}$, the total number of electrons will be 7 + 16 + 1 = 24 electrons.
In case of ${{N}_{2}}O$, the total number of electrons will be 14 + 8 = 22 electrons.
Hence the number of electrons of ${{N}_{2}}O$ is the same as $C{{O}_{2}}$which is 22 electrons.

Hence, the correct answer is Option D.

Note: The prefix ‘iso’ is used for organic compounds where all carbon atoms form a continuous chain except one. This carbon atom is considered to be a part of an isopropyl group at the end of the chain.