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Question: Which of the following ions does not liberate hydrogen gas on reaction with dilute acids? A. \[C{r...

Which of the following ions does not liberate hydrogen gas on reaction with dilute acids?
A. Cr2+C{r^{2 + }}
B. Mn2+M{n^{2 + }}
C. Ti2+T{i^{2 + }}
D. V2+{V^{2 + }}

Explanation

Solution

The comparison of electronegativities of the first-row transition metals will provide us the correct answer as we go from left to write the electronegativity increases. Thus, Sc is a rather active metal, on the other hand, Cu is much less reactive.

Complete step-by-step answer:
Exceptions to the overall trends are rather dependent on the stability associated with filled and half-filled subshells. The electron configuration of zinc is 4s23d104{s^2}3{d^{10}} results in its strong tendency to form the stable Zn2+  Z{n^{2 + }}\; ion, with the 3d10  3{d^{10}}\; electron configuration, whereas Cu+C{u^ + }, which also has the 3d10  3{d^{10}}\; electron configuration, in first-row transition metal only copper will from such positive ion. Similarly, with a half-filled subshell, Mn2+  (3d5)M{n^{2 + }}\;(3{d^5}) is much more difficult to oxidize thanFe2+  (3d6)F{e^{2 + }}\;(3{d^6}). The chemistry of manganese is therefore primarily that of the Mn2+  (3d5)M{n^{2 + }}\;(3{d^5}) ion, whereas both the Fe2+  andFe3+  F{e^{2 + }}\;and{\rm{ }}F{e^{3 + }}\;ions are important in the chemistry of iron. The reactivity of d-block metals increases from Mn2+  (3d5)M{n^{2 + }}\;(3{d^5})toTi+2  (3d2)to  V+2  (3d3)to  Cr+2(3d4)T{i^{ + 2}}\;\left( {3{d^2}} \right)to\;{V^{ + 2}}\;\left( {3{d^3}} \right)to\;C{r^{ + 2}}\left( {3{d^4}} \right). Therefore, the reactivity of Mn2+M{n^{2 + }}is very less. Therefore, Mn2+M{n^{2 + }} does not liberate hydrogen gas on reaction with dilute acids.

Hence, the option is (B) Mn2+M{n^{2 + }}, it does not liberate hydrogen gas on reaction with dilute acids.

Note: Metal reactivity series is the series based on the reactivity of the metals. The more reactive metals are kept at the top of the series followed by the ones with the lower reactivity. The more reactive a metal will be, the more will be its tendency to lose electrons. The metals in the metal reactivity series are arranged in the following manner; Group1 metals > group 2 metals > transition metals > least reactive metals.