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Question

Chemistry Question on Chemical bonding and molecular structure

Which of the following have identical bond order? (I) CNCN^- \quad (II) O2O_2 ^- \quad(III) NO+NO^+ \quad (IV) CN+CN^+

A

I, III

B

I, II

C

II, IV

D

I, II, III

Answer

I, III

Explanation

Solution

Isoelectronic species have same bond order. CN=6+7+1=14CN^- = 6 + 7 + 1 = 14 electrons, O2=8+8+1=17O_2^ - = 8 + 8 + 1 = 17 electrons, NO+=7+81=14NO^+ = 7 + 8 - 1 = 14 electrons, CN+=6+71=12CN^+ = 6 + 7 - 1 = 12 electrons.