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Question

Chemistry Question on Redox reactions

Which of the following have been arranged in decreasing order of oxidation number of sulphur?

A

Na2S4O6>H2S2O7>Na2S2O3>S8Na _{2} S _{4} O _{6}> H _{2} S _{2} O _{7}> Na _{2} S _{2} O _{3}> S _{8}

B

H2SO4>SO2>H2S>H2S2O8H _{2} SO _{4}> SO _{2}> H _{2} S > H _{2} S _{2} O _{8}

C

SO22+>SO42>SO32>HSO4SO _{2}^{2+}> SO _{4}^{2-}> SO _{3}^{2-}> HSO _{4}^{-}

D

H2SO5>H2SO3>SCl2>H2SH _{2} SO _{5}> H _{2} SO _{3}> SCl _{2}> H _{2} S

Answer

H2SO5>H2SO3>SCl2>H2SH _{2} SO _{5}> H _{2} SO _{3}> SCl _{2}> H _{2} S

Explanation

Solution

(a) Na2S4O62.5;H2S2O7+6;Na2S2O3+2;S80\overset{2.5}{Na _{2} S _{4} O _{6}} ; \overset{+6}{H _{2} S _{2} O _{7}} ; \overset{+2}{Na _{2} S _{2} O _{3}} ; \overset{0}{S _{8}}
(b) H2SO4+6+6;SO2+4;H2S2;H2S2O8+6\overset{+6}{H _{2} SO _{4}^{+6}} ; \overset{+4}{SO _{2}} ; \overset{-2}{H _{2} S} ; \overset{+6}{H _{2} S _{2} O _{8}}
(c) SO22++6;SO42+6;SO32+2;HSO4+6\overset{+6}{SO _{2}^{2+}} ; \overset{+6}{SO _{4}^{2-}} ; \overset{+2}{SO _{3}^{2-}} ; \overset{+6}{HSO _{4}^{-}}
(d) H2SO5+6;H2SO3+4;SCl2+2;H2S2\overset{+6}{H _{2} SO _{5}} ; \overset{+4}{H _{2} SO _{3}} ; \overset{+2}{SC l _{2}} ; \overset{-2}{H _{2} S}