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Question: Which of the following has the maximum number of unpaired d-electrons? (A) \(Z{{n}^{+2}}\) (B) \...

Which of the following has the maximum number of unpaired d-electrons?
(A) Zn+2Z{{n}^{+2}}
(B) Fe+2F{{e}^{+2}}
(C) Ni+3N{{i}^{+3}}
(D) Cu+C{{u}^{+}}

Explanation

Solution

As electronic configuration increases from [Ar]3d1\left[ Ar \right]3{{d}^{1}} to [Ar]3d5\left[ Ar \right]3{{d}^{5}},number of unpaired d electrons increases from 1 to 5. As electronic configuration moves from [Ar]3d6\left[ Ar \right]3{{d}^{6}} to [Ar]3d10\left[ Ar \right]3{{d}^{10}}, number of unpaired d electrons decreases from 4 to 0.

Complete solution step by step:
- Atomic number of zinc is 30. So, electronic configuration of zinc is [Ar]3d104s2\left[ Ar \right]3{{d}^{10}}4{{s}^{2}}.
- In divalent ion Zn+2Z{{n}^{+2}}, Zinc loses two electrons from 4s and electron configuration leads to[Ar]3d10\left[ Ar \right]3{{d}^{10}}. As all electrons are paired in d orbital, number of unpaired d electrons are zero.
- Atomic number of Iron is 26. Electronic configuration of Iron is [Ar]3d64s2\left[ Ar \right]3{{d}^{6}}4{{s}^{2}}.
- In divalent ion Fe+2F{{e}^{+2}},iron loses two electrons from 4s and electron configuration becomes [Ar]3d6\left[ Ar \right]3{{d}^{6}},As only two electrons are paired in 3d orbital, number of unpaired d electrons are four.
- Atomic number of Nickel is 28. Electronic configuration if nickel is[Ar]3d84s2\left[ Ar \right]3{{d}^{8}}4{{s}^{2}}.
- In trivalent ions, nickel loses three electrons, two electrons from 4s and one electron from 3d. Electronic configuration becomes [Ar]3d7\left[ Ar \right]3{{d}^{7}}. Number of unpaired d electrons are three.
- Atomic number of Copper is 29. Expected electronic configuration of copper is [Ar]3d94s2\left[ Ar \right]3{{d}^{9}}4{{s}^{2}}and observed electronic configuration of copper is [Ar]3d104s1\left[ Ar \right]3{{d}^{10}}4{{s}^{1}}. To gain extra stability, one electron from 4s is transferred to 3d.
In Monovalent ion, Copper loses one electron from 4s and electronic configuration of copper becomes [Ar]3d10\left[ Ar \right]3{{d}^{10}}.As all electrons are paired in 3d orbital, number of unpaired d electron is zero.
As, Fe+2F{{e}^{+2}} has four unpaired electrons, option (B) Fe+2F{{e}^{+2}} has a maximum number of unpaired d-electrons.

Note: Chromium and copper have an exception of half-filled and completely filled d orbitals respectively. Zinc has completely filled d orbital and zero unpaired d electrons. To gain extra stability, one 4s electron is transferred to 3d so copper has completely filled d orbitals and zero unpaired d electrons. Chromium has half-filled d orbitals and the number of unpaired d electrons is five.