Question

Which of the following has the largest bond angle?
A.${H_2}O$
B.${F_2}O$
C.$C{l_2}O$
D.${H_2}S$

Answer 1

We need to know that the bond angle is the angle present between two bonds which is occupied in a covalent species. Hence, there should be at least two bonds in that covalent species. The lone pair repulsion mainly affects the bond angle. Therefore, if the central atom contain the lone pair of electrons, the angle of the compound will be decrease.

Complete answer:
Water is a chemical element having the symbol ${H_2}O$. The bond angle of water is equal to $104.5^\circ$ and it does not have the largest bond angle. Hence, option (A) is incorrect.
Oxygen difluoride is a chemical element having the symbol ${F_2}O$. The bond angle of water is equal to $102^\circ$ and it does not have the largest bond angle. Hence, option (B) is incorrect.
Among the given compounds, the $C{l_2}O$ has the largest bond angle and which is equal to $109.5^\circ$. The largest bond angle of chlorine monoxide is because of the presence of large lone pair – bond pair repulsion. And it will increase the bond angle of chlorine monoxide. And this type of repulsion also depends upon the electronegativity. Hence, option (C) is correct.
Hydrogen sulphide is a chemical element having the symbol ${H_2}S$. The bond angle of water is equal to $90^\circ$ and it does not have the largest bond angle. Hence, option (D) is incorrect.

Hence, option (C) is correct.

Note:
We need to remember that the bond angle mainly depends on the shape and hybridization of a compound. If the compounds have the same hybridization, then the sum of lone pair and bond pair is equal to the same. Hence, the bond angle becomes equal. And the electronegativity and shape of molecules also affect the bond angle. The bond angle decreases with decreasing electronegativity.