Question

which of the following has $p \pi-d \pi$ bonding?

• A. $NO_{3}^{-}$
• B. $SO_{3}^{2-}$
• C. $BO_{3}^{3-}$
• D. $CO_{3}^{2-}$

Answer 1

Answer: (B)

$SO_{3}^{2-}$

Answer 2

In $SO _{3}^{2-}$ d-orbital of $S$ atom overlaps with $p$-orbital of $O$-atom to form a $\pi$-bond hence, $SO _{3}^{2-}$ has $p \pi-d \pi$ bonding.