Question

Which of the following gas will have highest rate of diffusion

• A. $Z = \frac{pV_{m}}{RT} = 1 - \frac{ap}{(RT)^{2}}$
• B. $Z = \frac{pV_{m}}{RT} = 1 + \frac{b}{RT}p$
• C. $pV_{m} = RT$
• D. $Z = \frac{pV_{m}}{RT} = 1 - \frac{a}{RT}$

Answer 1

Answer: (A)

$Z = \frac{pV_{m}}{RT} = 1 - \frac{ap}{(RT)^{2}}$

Answer 2

m. wt. of $\overline{K.E.}$; m.wt. of $N_{2}$

m.wt. of ${\overline{KE}}_{CO} = {\overline{KE}}_{N_{2}}$; m.wt. of ${\overline{KE}}_{CO} > {\overline{KE}}_{N_{2}}$

beacuse ${\overline{KE}}_{CO} < {\overline{KE}}_{N_{2}}$is lightest gas out of these gases

$N_{2}(g)$