Question
Question: Which of the following does not give the iodoform test? A. \({{\text{C}}_{2}}{{\text{H}}_{5}}\text...
Which of the following does not give the iodoform test?
A. C2H5OH
B. C6H5OH
C. (CH3)2CHOH
D. All of the above
Solution
Iodoform test is used to test whether the carbonyl group or alcohol group is present or not in the molecule. The compound with ketone and alcohol groups will give a positive test for the iodoform. Iodine along with a base is used as a reactant.
Complete answer:
- In the given question, we have to identify the molecule which will not give the positive test for iodine.
- Iodoform test is used to identify the presence of a carbonyl such as R - CO - CH3 or alcohol group such as R - CH(OH)-.
- When iodine, a base such as sodium hydroxide is combined with the compound containing methyl ketone or secondary alcohol which has a methyl group.
- Then they form a precipitate of yellow coloured triiodomethane which confirms the presence of the carbonyl group.
- With ethyl alcohol:
CH3CHOH + I2 + NaOH → CHI3 + COONa
- With (CH3)2CHOH
(CH3)2CHOH + I2 + NaOH → CHI3+ CH3COONa
- whereas not only ketogenic or alcoholic groups but the aldehyde such as acetaldehyde can also give the positive iodoform test because it consists of a methyl group attached to the carbonyl, CH3 - C=O.
- So, among the given options only option B will not give the positive iodoform test because there is no presence of the methyl group in the molecule.
- Whereas in option A and B, a methyl group is present as we can see
CH3CHOH and CH3C = O.
Therefore, option B is the correct answer.
Note:
As we know that iodine has antiseptic properties. So, in ancient times the iodoform was used as a disinfectant to kill the bacteria and an antiseptic to heal the wounds. Moreover, iodoform has a saffron-like structure with hexagonal structure.