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Question: Which of the following contains three centre and two electron bonds? (A)- \({\left( {{\text{Be}}{{...

Which of the following contains three centre and two electron bonds?
(A)- (BeH2)2{\left( {{\text{Be}}{{\text{H}}_{\text{2}}}} \right)_{\text{2}}}
(B)- LiAlH4{\text{LiAl}}{{\text{H}}_{\text{4}}}
(C)- (BeCl2)2{\left( {{\text{BeC}}{{\text{l}}_{\text{2}}}} \right)_2}
(D)- Li2C2{\text{L}}{{\text{i}}_{\text{2}}}{{\text{C}}_{\text{2}}}

Explanation

Solution

As the name suggests, ‘three centre and two electron bonds’ means we have to choose that compound in which 3 centers is presented as atoms and 2 bonds is present in the given compound.

Complete step by step solution: Three centre and two electron bonds containing compounds are generally electron deficient in nature because 2 electrons are shared in between three atoms.
Among the given options in the question option (A) i.e. (BeH2)2{\left( {{\text{Be}}{{\text{H}}_{\text{2}}}} \right)_{\text{2}}}is correct, below is given some important points which throw light on the reason:
- Atomic no. of Beryllium (Be) atoms is 4 and its electronic configuration is1s22s21{s^2}2{s^2} .
- There are 2 electrons in the valence shell, it means we use these 2 electrons for the formation of bonds.
- Among these 2 electrons, one electron forms a covalent bond with one hydrogen atom and another electron is used to form a banana bond with another hydrogen atom.
- In the given compound(BeH2)2{\left( {{\text{Be}}{{\text{H}}_{\text{2}}}} \right)_{\text{2}}}, total no. of Be atom is 2 and total no. of hydrogen atom is 4; among which 2 hydrogen forms covalent bond & another 2 takes part in the formation of banana bond.
- One Banana bond is formed by the 2 electrons between the 3 atoms but there is no uniform distribution of electrons among all 3 atoms, it is more towards the 2 atoms only.
- The structure of (BeH2)2{\left( {{\text{Be}}{{\text{H}}_{\text{2}}}} \right)_{\text{2}}}is shown as:


- Here Be has sp2s{p^2} hybridization.
- Be-H-Be is a 3 centre between them 2 electron bonds are present, which is known as banana bond.

So, option A is the correct answer.

Note: In this question it is mentioned that between 3 centre, 2 electron bonds is present so never confuse with the Be-H bond because in this bond 2 centre is only present. And as Be forms 3 bonds but among these 3 bonds, electrons are not present in that bond which is shown by the dash line.