Question
Question: Which of the following contains the least number of molecules \( ? \) (A) \( 3.2\,g\,S{O_2} \) ...
Which of the following contains the least number of molecules ?
(A) 3.2gSO2
(B) 3.4gNH3
(C) 1.6gCH4
(D) 3.2gSO2
Solution
Hint : To solve the above question, we must understand the mole concept. Mole (mol) is the measure of the amount of substance present in a material. A mole contains 6.022×1023 number of entities which can be atoms, molecules or ions. The number 6.022×1023 is known as Avogadro’s number (NA) .
Complete Step By Step Answer:
From the hint given, we understood that a mole is the amount of a substance that contains 6.022×1023 particles. In order to find out which compound contains the least number of molecules, we must calculate the number of moles present in them.
Number of moles , n=molarmass(M)givenmass(m)
Also, n=Avogadronumber(NA)numberofmolecules(N)
Therefore, number of molecules (N) =Mm×NA
First, we have to calculate the molar masses of given compounds and then substitute it in the given equation. The molar mass of compounds are :
CO2=44gmol−1 NH3=17gmol−1 CH4=16gmol−1 SO2=64gmol−1
Number of molecules in CO2 =444.4×NA=0.1NA
Number of molecules in NH3=173.4×NA=0.2NA
Number of molecules in CH4=161.6×NA=0.1NA
Number of molecules in SO2=643.2×NA=0.05NA
NA=6.022×1023 molecules
Therefore, the right option is (D) 3.2gSO2 . It contains the least number of molecules.
Note :
Molar mass (M) is the mass of one mole of a substance, or mass of 6.022×1023 number of entities. It is expressed in gmol−1 .It is often used interchangeably with molecular mass. Molecular mass is defined as the mass of a single molecule. The unit of molecular mass is given in atomic mass units (amu).
Given, the compounds are present in equal quantity (equal grams), then the molecule having higher molar mass will contain the least number of molecules.