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Question: Which of the following contains the largest mass of hydrogen atoms? A.\(0.5{\text{ moles }}{{\tex...

Which of the following contains the largest mass of hydrogen atoms?
A.0.5 moles C2H2O40.5{\text{ moles }}{{\text{C}}_{\text{2}}}{{\text{H}}_{\text{2}}}{{\text{O}}_{\text{4}}}
B.1.1 moles C3H8O3{\text{1}}{\text{.1 moles }}{{\text{C}}_3}{{\text{H}}_8}{{\text{O}}_3}
C.1.5 moles C6H8O61.5{\text{ moles }}{{\text{C}}_6}{{\text{H}}_8}{{\text{O}}_6}
D.4.0 moles C3H8O3{\text{4}}{\text{.0 moles }}{{\text{C}}_3}{{\text{H}}_8}{{\text{O}}_3}

Explanation

Solution

A mole of a substance is the mass of a substance that contains exactly the same number of fundamental units, as in 12.0 g of C. The subscript of atom in the molecular formula indicates the number of moles of atom in one mole of formula.

Formula Used:
Mass of atom = moles \timesatomic mass{\text{Mass of atom = moles \times atomic mass}}

Complete step-by-step answer: Calculate the mass of H atoms in0.5 moles C2H2O40.5{\text{ moles }}{{\text{C}}_{\text{2}}}{{\text{H}}_{\text{2}}}{{\text{O}}_{\text{4}}}.
The molecular formula of the compound indicates that 1 mole C2H2O4{{\text{C}}_{\text{2}}}{{\text{H}}_{\text{2}}}{{\text{O}}_{\text{4}}} contains 2 moles of H{\text{H}} atoms.
So, 0.5 moles C2H2O4×2 mol H atom 1 moles C2H2O4 = 1.0 mol H atoms{\text{0}}{\text{.5 moles }}{{\text{C}}_{\text{2}}}{{\text{H}}_{\text{2}}}{{\text{O}}_{\text{4}}} \times \dfrac{{{\text{2 mol H atom }}}}{{1{\text{ moles }}{{\text{C}}_{\text{2}}}{{\text{H}}_{\text{2}}}{{\text{O}}_{\text{4}}}}}{\text{ = 1}}{\text{.0 mol H atoms}}
Now, convert these moles of H{\text{H}} atom to mass of H{\text{H}} atoms as follows:
Mass of atom = moles × atomic mass{\text{Mass of atom = moles }} \times {\text{ atomic mass}}
The atomic mass of H{\text{H}} atom = 1.0 g/mol1.0{\text{ g/mol}}
Thus,
Mass of H atoms = 1.0 mol H atoms × 1.0 g/mol{\text{Mass of H atoms = 1}}{\text{.0 mol H atoms }} \times {\text{ 1}}{\text{.0 g/mol}}
Mass of H atoms = 1.0 g{\text{Mass of H atoms = 1}}{\text{.0 g}}
Hence, 0.5 moles C2H2O40.5{\text{ moles }}{{\text{C}}_{\text{2}}}{{\text{H}}_{\text{2}}}{{\text{O}}_{\text{4}}} contain 1.0 g{\text{1}}{\text{.0 g}} of H{\text{H}} atoms.
Calculate the mass of H atoms in 1.1 moles C3H8O3{\text{1}}{\text{.1 moles }}{{\text{C}}_3}{{\text{H}}_8}{{\text{O}}_3}.
The molecular formula of the compound
indicates that 1 mole C3H8O3{{\text{C}}_3}{{\text{H}}_8}{{\text{O}}_3} contains 8 moles of H{\text{H}} atoms.
So, 1.1 moles C3H8O3×8 mol H atom 1 moles C3H8O3 = 8.8 mol H atoms{\text{1}}{\text{.1 moles }}{{\text{C}}_3}{{\text{H}}_8}{{\text{O}}_3} \times \dfrac{{{\text{8 mol H atom }}}}{{1{\text{ moles }}{{\text{C}}_3}{{\text{H}}_8}{{\text{O}}_3}}}{\text{ = 8}}{\text{.8 mol H atoms}}
Now, convert these moles of H{\text{H}} atom to mass of H{\text{H}} atoms as follows:
Mass of H atoms = 8.8 mol H atoms × 1.0 g/mol{\text{Mass of H atoms = 8}}{\text{.8 mol H atoms }} \times {\text{ 1}}{\text{.0 g/mol}}
Mass of H atoms = 8.8 g{\text{Mass of H atoms = 8}}{\text{.8 g}}
Hence, 1.1 moles C3H8O3{\text{1}}{\text{.1 moles }}{{\text{C}}_3}{{\text{H}}_8}{{\text{O}}_3} contain 8.8 g{\text{8}}{\text{.8 g}} of H{\text{H}} atoms.
Calculate the mass of H atoms in 1.5 moles C6H8O61.5{\text{ moles }}{{\text{C}}_6}{{\text{H}}_8}{{\text{O}}_6}.
The molecular formula of the compound indicates that 1 mole C6H8O6{{\text{C}}_6}{{\text{H}}_8}{{\text{O}}_6} contains 8 moles of H{\text{H}} atoms.
So, 1.5 moles C6H8O6×8 mol H atom 1 moles C3H8O3 = 12 mol H atoms{\text{1}}{\text{.5 moles }}{{\text{C}}_6}{{\text{H}}_8}{{\text{O}}_6} \times \dfrac{{{\text{8 mol H atom }}}}{{1{\text{ moles }}{{\text{C}}_3}{{\text{H}}_8}{{\text{O}}_3}}}{\text{ = 12 mol H atoms}}
Now, convert these moles of H{\text{H}} atom to mass of H{\text{H}} atoms as follows:
Mass of H atoms = 12 mol H atoms \times1.0 g/mol{\text{Mass of H atoms = 12 mol H atoms \times 1}}{\text{.0 g/mol}}
Mass of H atoms = 12 g{\text{Mass of H atoms = 12 g}}
Hence, 1.5 moles C6H8O61.5{\text{ moles }}{{\text{C}}_6}{{\text{H}}_8}{{\text{O}}_6} contain 12.0 g{\text{12}}{\text{.0 g}} of H{\text{H}} atoms.
Calculate the mass of H atoms in 4.0 moles C3H8O3{\text{4}}{\text{.0 moles }}{{\text{C}}_3}{{\text{H}}_8}{{\text{O}}_3}.
The molecular formula of the compound indicates that 1 mole C3H8O3{{\text{C}}_3}{{\text{H}}_8}{{\text{O}}_3} contains 8 moles of H{\text{H}} atoms.
So, 4.0 moles C3H8O3×8 mol H atom 1 moles C3H8O3 = 32 mol H atoms{\text{4}}{\text{.0 moles }}{{\text{C}}_3}{{\text{H}}_8}{{\text{O}}_3} \times \dfrac{{{\text{8 mol H atom }}}}{{1{\text{ moles }}{{\text{C}}_3}{{\text{H}}_8}{{\text{O}}_3}}}{\text{ = 32 mol H atoms}}
Now, convert these moles of H{\text{H}} atom to mass of H{\text{H}} atoms as follows:
Mass of H atoms = 32 mol H atoms × 1.0 g/mol{\text{Mass of H atoms = 32 mol H atoms }} \times {\text{ 1}}{\text{.0 g/mol}}
Mass of H atoms = 32 g{\text{Mass of H atoms = 32 g}}
Hence, 4.0 moles C3H8O3{\text{4}}{\text{.0 moles }}{{\text{C}}_3}{{\text{H}}_8}{{\text{O}}_3} contain 32 g{\text{32 g}} of H{\text{H}} atoms.
Now, by comparing the mass ofH{\text{H}} atoms calculated for each compound we can say that 4.0 moles C3H8O3{\text{4}}{\text{.0 moles }}{{\text{C}}_3}{{\text{H}}_8}{{\text{O}}_3} contain the largest mass of hydrogen atoms.

Thus, the correct option is (D) 4.0 moles C3H8O3{\text{4}}{\text{.0 moles }}{{\text{C}}_3}{{\text{H}}_8}{{\text{O}}_3}

Note: The mass of H{\text{H}} atom in compounds containing the same number of moles of H atom depends on the moles of compounds. A compound having a greater number of moles will contain a greater number of H{\text{H}} atoms and thus greater mass of H atoms.