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Question: Which of the following compound have \({\text{X}} - {\text{O}} - {\text{X}}\) linkage where ‘\({\tex...

Which of the following compound have XOX{\text{X}} - {\text{O}} - {\text{X}} linkage where ‘X{\text{X}}’ is the so called central atom like P{\text{P}}, S{\text{S}} etc?
(A) P2O84{{\text{P}}_{\text{2}}}{\text{O}}_8^{4 - }
(B) S2O32{{\text{S}}_{\text{2}}}{\text{O}}_3^{2 - }
(C) γSO3\gamma - {\text{S}}{{\text{O}}_3}
(D) S2O52{{\text{S}}_{\text{2}}}{\text{O}}_5^{2 - }

Explanation

Solution

To solve this we must first draw the structures of all the four given compounds. From the structures we can determine the compound having XOX{\text{X}} - {\text{O}} - {\text{X}} linkage. First of all we should draw the exact structure of the compound to find out the central atom.

Complete Step by step answer: P2O84{{\text{P}}_{\text{2}}}{\text{O}}_8^{4 - } is known as peroxydisulfate ion. Draw the structure of P2O84{{\text{P}}_{\text{2}}}{\text{O}}_8^{4 - }:

In the structure of P2O84{{\text{P}}_{\text{2}}}{\text{O}}_8^{4 - }, we cannot see POP{\text{P}} - {\text{O}} - {\text{P}} linkage. Thus, P2O84{{\text{P}}_{\text{2}}}{\text{O}}_8^{4 - } does not have XOX{\text{X}} - {\text{O}} - {\text{X}} linkage.
Thus, option (A) is not correct.
S2O32{{\text{S}}_{\text{2}}}{\text{O}}_3^{2 - } is known as thiosulphate ion. Draw the structure of S2O32{{\text{S}}_{\text{2}}}{\text{O}}_3^{2 - }:

In the structure of S2O32{{\text{S}}_{\text{2}}}{\text{O}}_3^{2 - }, we cannot see SOS{\text{S}} - {\text{O}} - {\text{S}} linkage. Thus, S2O32{{\text{S}}_{\text{2}}}{\text{O}}_3^{2 - } does not have XOX{\text{X}} - {\text{O}} - {\text{X}} linkage.
Thus, option (B) is not correct.
γSO3\gamma - {\text{S}}{{\text{O}}_3} is known as sulphur trioxide. Draw the structure of γSO3\gamma - {\text{S}}{{\text{O}}_3}:

In the structure of γSO3\gamma - {\text{S}}{{\text{O}}_3}, we can see SOS{\text{S}} - {\text{O}} - {\text{S}} linkage. The SOS{\text{S}} - {\text{O}} - {\text{S}} is shown in red colour. Thus, γSO3\gamma - {\text{S}}{{\text{O}}_3} has XOX{\text{X}} - {\text{O}} - {\text{X}} linkage.
Thus, option (C) is correct.
S2O52{{\text{S}}_{\text{2}}}{\text{O}}_5^{2 - } is known as metabisulphite. Draw the structure of S2O52{{\text{S}}_{\text{2}}}{\text{O}}_5^{2 - }:

In the structure of S2O52{{\text{S}}_{\text{2}}}{\text{O}}_5^{2 - }, we cannot see SOS{\text{S}} - {\text{O}} - {\text{S}} linkage. Thus, S2O52{{\text{S}}_{\text{2}}}{\text{O}}_5^{2 - } does not have XOX{\text{X}} - {\text{O}} - {\text{X}} linkage.
Thus, option (D) is not correct.
Thus, the compound have XOX{\text{X}} - {\text{O}} - {\text{X}} linkage where ‘X{\text{X}}’ is the so called central atom like P{\text{P}}, S{\text{S}} etc is γSO3\gamma - {\text{S}}{{\text{O}}_3}.

Thus, the correct option is (C) γSO3\gamma - {\text{S}}{{\text{O}}_3}.

Note: Sulphur trioxide (SO3)\left( {{\text{S}}{{\text{O}}_3}} \right) has many structural changes and thus, it has many different forms. These changes are caused by the traces of water. γSO3\gamma - {\text{S}}{{\text{O}}_3} is very pure gaseous sulphur trioxide. It is a trimeric structure i.e. it has three molecules of sulphur trioxide. γSO3\gamma - {\text{S}}{{\text{O}}_3} forms a cyclic structure. It is colourless solid in appearance. Sulphur trioxide is highly hygroscopic in nature i.e. it can easily attract water molecules from its surroundings by absorption or adsorption.