Question

Which of the following compound has all the four types $\left(1^{\circ}, 2^{\circ}, 3^{\circ}\right.$ and $\left.4^{\circ}\right)$ of carbon atoms?

• A. 2, 3, 4-Trimethylpentane
• B. neo-Pentane
• C. 2, 2, 4-Trimethylpentane
• D. None of the three

Answer 1

Answer: (C)

2, 2, 4-Trimethylpentane

Answer 2

$C_1$ and $C_5$ are $1^{\circ}, C_3$ is $2^{\circ}, C_4$ is $3^{\circ},$ and $C_2$ is $4^{\circ}$.