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Question

Physics Question on thermal properties of matter

Which of the following circular rods, (given radius rr and length ll each made of the same material and whose ends are maintained at the same temperature will conduct most heat?

A

r=2r0;l=2l0r=2r_{0};\,\,l=2l_{0}

B

r=2r0;l=l0r=2r_{0};l=l_{0}

C

r=r0;l=l0r=r_{0};l=l_{0}

D

r=r0;l=2l0r=r_{0};l=2l_{0}

Answer

r=2r0;l=l0r=2r_{0};l=l_{0}

Explanation

Solution

Heat conduction through a rod is given by
H=ΔQΔt=KA(T1T2l)H=\frac{\Delta Q}{\Delta t}=K A\left(\frac{T_{1}-T_{2}}{l}\right)
Hr2l\Rightarrow H \propto \frac{r^{2}}{l} \ldots(i)
(a) When r=2r0;l=2l0r=2 r_{0} ; l=2 l_{0}
H(2r0)22l0H \propto \frac{\left(2 r_{0}\right)^{2}}{2 l_{0}}
H2r02l0\Rightarrow H \propto \frac{2 r_{0}^{2}}{l_{0}}
(b) When r=2r0;l=l0r=2 r_{0} ; l=l_{0}
H(2r0)2l0H \propto \frac{\left(2 r_{0}\right)^{2}}{l_{0}}
H4r02l0\Rightarrow H \propto \frac{4 r_{0}^{2}}{l_{0}}
(c) When r=r0;l=l0r=r_{0} ; l=l_{0}
Hr02l0H \propto \frac{r_{0}^{2}}{l_{0}}
(d) When r=r0;l=2l0r=r_{0} ; l=2 l_{0}
Hr022l0H \propto \frac{r_{0}^{2}}{2 l_{0}}
It is obvious that heat conduction will be more in case (b).