Question
Question: Which of the following carbocation is most stable? (A)- \({{(C{{H}_{3}})}_{3}}C-CH_{2}^{+}\) (B...
Which of the following carbocation is most stable?
(A)- (CH3)3C−CH2+
(B)- (CH3)3C+
(C)- CH3CH2CH2+
(D)- CH3CH+CH2CH3
Solution
Carbocations are positive charged species formed as a result of heterolytic cleavage of bonds. Alkyl groups stabilize a carbocation by electron releasing effect. Stability of carbocations depends on the extent of dispersal of the positive charge and follows the order
3ocarbocation>2ocarbocation>1ocarbocation
Complete step by step solution:
Depending on the type of carbon bearing positive, carbocations can be primary (1o), secondary (2o) and tertiary (3o). 1o, 2o and 3o carbocation has positively charged carbon bonded to one, two and three other carbon groups, i.e.
R−CH2+ 1o R−CH+−R2oR3C+3o
Stability of carbocations can be explained by inductive effect (+I effect). An alkyl group is electron releasing in nature. So alkyl groups attached to a carbon bearing positive charge tend to stabilize that positive charge on the carbon. In doing so, the positive charge is dispersed on the alkyl groups. Now if a greater number of alkyl groups is attached to the positively charged carbon, there will be greater dispersal of positive charge on the alkyl groups and hence, more will be the stability of the carbocation.
Therefore, 3o carbocation is most stable followed by 2o and 1o carbocations.
Let us look at the options given and classify them into 1o, 2o and 3o carbocation.
(CH3)3C−CH2+ and CH3CH2CH2+ have only one alkyl groups attached (1o) and thus have less +I effect.
CH3CH+CH2CH3 has two alkyl, i.e. one methyl and one ethyl group attached. Thus, being 2ocarbocation it shows more +I effect than 1o carbocation.
(CH3)3C+ is 3o carbocation as it has three methyl groups. +I effect will be more in case of (CH3)3C+ than 1oand 2o carbocations.
Therefore, (CH3)3C+ is the most stable carbocation.
Hence, the correct option is (B)
Note: Carefully classify the given carbocations into 1o, 2o and 3o to determine the stability. Greater the dispersal of positive charge more is the stability of the carbocation. Stability of carbocations that are attached to a benzene ring or double bond is explained by resonance and hyperconjugation effects.