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Chemistry Question on Classification

Which of the following arrangements represents the increasing order (smallest to largest) of ionic radii of the given species O2−,S2−,N3−,P3−?O^{2-}, S^{2-}, N^{3-}, P^{3-} ?

A

O2−<N3−<S2−<P3−O^{2-} < N^{3-} < S^{2-} < P^{3-}

B

O2−<P3−<N3−<S2−O^{2-} < P^{3-} < N^{3-} < S^{2-}

C

N3−<O2−<P3−<S2−N^{3-} < O^{2-} < P^{3-} < S^{2-}

D

N3−<S2−<O2−<P3−N^{3-} < S^{2-} < O^{2-} < P^{3-}

Answer

O2−<N3−<S2−<P3−O^{2-} < N^{3-} < S^{2-} < P^{3-}

Explanation

Solution

For isoelectronic species ionic radii decreases as the charge on ion decreases. Further on moving down in a group ionic radii increases. Hence the correct order is
O2−<N3−<S2−<P3−O^{2-} < N^{3-} < S^{2-} < P^{3-}