Question

Which of the following are the products shown by the reaction of methoxyethane with HI?

• A. $\mathrm { C } _ { 2 } \mathrm { H } _ { 5 } \mathrm { I } + \mathrm { CH } _ { 3 } \mathrm { OH }$
• B. $\mathrm { CH } _ { 3 } \mathrm { I } + \mathrm { H } _ { 2 } \mathrm { O }$
• C. $\mathrm { C } _ { 2 } \mathrm { H } _ { 5 } \mathrm { OH } + \mathrm { H } _ { 2 } \mathrm { O }$
• D. $\mathrm { C } _ { 2 } \mathrm { H } _ { 5 } \mathrm { OH } + \mathrm { Cl } _ { 3 } \mathrm { I }$

Answer 1

Answer: (A)

$\mathrm { C } _ { 2 } \mathrm { H } _ { 5 } \mathrm { I } + \mathrm { CH } _ { 3 } \mathrm { OH }$

Answer 2

$\mathrm { C } _ { 2 } \mathrm { H } _ { 5 } \mathrm { OCH } _ { 3 } + \mathrm { HI } \rightarrow \mathrm { C } _ { 2 } \mathrm { H } _ { 5 } \mathrm { OH } + \mathrm { CH } _ { 3 } \mathrm { I }$

Halogen goes with the smaller group on cleavage of ether.