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Question: Which of the following anions is orange in color? (A) \(HSO_4^-\)​ (B) \(MnO_4\)​ (c) \(Cr_2O_...

Which of the following anions is orange in color?
(A) HSO4HSO_4^-
(B) MnO4MnO_4
(c) Cr2O72Cr_2O_7^{2-}​​
(D) All of the above

Explanation

Solution

Color in an ion is possible only if it contains a transition metal in it. Transition metals are the dd-block elements that lie between the metals and nonmetals in the periodic table. They show a transition from metals to nonmetals. Hence, the name transition elements.

Complete step by step answer:
Among the given options, Cr2O72Cr_2O_7^{2-} is orange in color. Cr2O72Cr_2O_7^{2-} anion is called the dichromate ion. Transition metal ions show color due to the presence of incompletely or half-filled dd-orbitals. Let us check the filling of dd- block orbitals in the chromium ion. The atomic number of chromium is 2424. Its electronic configuration is [Ar]3d6[Ar]3d^6. So, it has an incompletely filled dd-orbital. When a metal forms a bond with the anion, the degenerate dd- orbitals which were earlier in the same energy level, now get split into two different energy levels, namely, t2gt_2g and ege_g. The electrons now jump from the lower t2gt_2g orbital to the higher ege_g orbital. In doing so, the electron absorbs energy. Now, an electron cannot stay in the higher orbital and tends to jump back to its lower orbital immediately by releasing the absorbed energy. In the case of dichromate ions, the color released by the chromium ion while jumping from a higher t2gt_2g orbital to a lower ege_g orbital is orange. Therefore, the anion that is orange in color is Cr2O72Cr_2O_7^{2-}.

So, the correct answer is Option C .

Note: 1.The dd-orbital has 55 degenerate orbitals. Degenerate orbitals are the orbitals that have the same energy. When a metal approaches a transition metal ion, the five degenerate dd-orbitals split into three higher and two lower energy level orbitals, called the generated orbitals. This is the principle of the crystal field theory.
2.The anion HSO4HSO_4^- consists of the metal ion, H+H^+, which is not a transition metal. Hence, the anion does not show any color.
3.The anion MnO4MnO_4^- consists of Mn+7Mn^{+7} as the transition metal ion, but it is not orange in color. The anion is purple.