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Question

Chemistry Question on Colligative Properties

Which of the following 0.10 m aqueous solution will have the lowest freezing point ?

A

Al2(SO4)3Al_2(SO_4)_3

B

C6H12O6C_6H_{12}O_6

C

C12H12O11C_{12}H_{12}O_{11}

D

KIKI

Answer

Al2(SO4)3Al_2(SO_4)_3

Explanation

Solution

Depression in freezing point is a colligative property which depends upon the amount of the solute. ΔTf=i×Kf×m\Delta T _{ f }= i \times K _{ f } \times m i(C12H22O11)=1,i(KI)=2,i(Al2(SO4)3)=5,i(C5H10O5)=1i _{\left( C _{12} H _{22} O _{11}\right)}=1, i _{( KI )}=2, i _{\left( Al _{2}\left( SO _{4}\right)_{3}\right)}=5, i _{\left( C _{5} H _{10} O _{5}\right)}=1 as, ΔTfαi\Delta T _{ f } \alpha i thus, ΔTf(max)\Delta T _{ f }(\max ) is for 0.10m0.10 m alluminium sulphate and Hence, has lowest Freezing point.