Question

Which of following lines correctly show the temperature dependence of equilibrium constant $K$, for an exothermic reaction ?

• A. A and B
• B. B and C
• C. C and D
• D. A and D

Answer 1

Answer: (A)

A and B

Answer 2

Equilibrium constant $K =\left(\frac{ A _{ f }}{ A _{ b }}\right) e ^{-\frac{\Delta H ^{\circ}}{ RT }}$ ln $K =$ ln $\left(\frac{ A _{ f }}{ A _{ b }}\right)-\frac{\Delta H ^{\circ}}{ R }\left(\frac{1}{ T }\right)$ $y = C + m x$ Comparing with equation of straight line, Slope $=\frac{-\Delta H^{\circ}}{R}$ Since, reaction is exothermic, $\Delta H ^{\circ}=- ve$, therefore, slope $= +ve$