Question
Question: Which is not the correct relation between enthalpy \[\left( {\Delta {\text{H}}} \right)\] and intrin...
Which is not the correct relation between enthalpy (ΔH) and intrinsic energy (ΔE)
A.ΔH=ΔE+PΔV
B.ΔH=ΔE+nRT
C.ΔH=ΔE−PΔV
D.ΔE=ΔH−PΔV
Solution
To answer this we must know the relation between enthalpy and intrinsic energy. Rearranging the formula will give us the above mentioned options; one of them is incorrectly represented. Take the help of the ideal gas equation.
Formula used: ΔH=ΔE+PΔV
Here Enthalpy is (ΔH) and intrinsic energy or internal energy is (ΔE) , P is pressure and V is volume.
Complete step by step answer:
The actual relationship between the enthalpy and the energy is as follow:
ΔH=ΔE+PΔV
So, the given relation in option A stands correct.
Now if we rearrange the formula by moving the factor PΔV to the enthalpy side. We need to put the negative sign before PΔV . The equation will become:
ΔE=ΔH−PΔV
This is the same as the option D. So option D is also correct.
We know the ideal gas equation. The ideal gas equation says that:
PΔV=nRT
We can substitute the value of PΔV in the main formula. We will get the following equation:
ΔH=ΔE+nRT
Hence, the given option B is correct.
There is no possible arrangement in which we can get the option C. Hence it is incorrect representation.
Thus, the correct option is C.
Note:
Enthalpy is defined as the sum of internal energy and product of pressure and volume. The heat absorbed or released in a system at constant pressure is known as enthalpy change. The energy present or stored within a substance is known as internal energy. Internal energy is a state function and is an extensive quantity. This means it depends upon the quantity of material and not on the nature. The negative of PΔV is known as work done in thermodynamics.