Question

Which is incorrect statement regarding ${B_2H_6}$ ?

• A. It is a strong reducing agent
• B. On heating, it gives amorphous boron
• C. It is a planar molecule
• D. With excess $\ce{(CH_3)_3N}$, it undergoes symmetrical cleavage

Answer 1

Answer: (C)

It is a planar molecule

Answer 2

Four $H_t$ and two $B$ atoms lie in the same plane while two bridging H atoms $(H_b)$ lie in a plane perpendicular to the rest of the molecule. Thus, ${B_2H_6}$ is not a planar molecule.