Question

Which is correct option for overlapping strength

• A. 2s - 2s < 2s - 2p < 2p - 2p
• B. 1s – 1s < 1s – 2p < 1p - 2р
• C. 2s - 2s < 1s - 2p < 1s - 1s
• D. Both (A) and (C)

Answer 1

Answer: (A), (C), (D)

D

Answer 2

Overlapping strength depends on orbital size (smaller n is better), directional nature (p-p > s-p > s-s), and extent of overlap.

(A) 2s-2s < 2s-2p < 2p-2p is correct because for same 'n', directional overlap is stronger: s-s < s-p < p-p (axial).

(C) 2s-2s < 1s-2p < 1s-1s is correct. 1s-1s is strongest due to compact orbitals. 2s-2s is weakest of the three due to larger, diffuse, non-directional 2s orbitals. 1s-2p is stronger than 2s-2s due to the highly concentrated 1s orbital and directional 2p orbital, but weaker than 1s-1s due to size mismatch.