Question

Which is / are true statements / reaction?
(This question has multiple correct options)
A. $\;\;\;{\mathbf{A}}{{\mathbf{l}}_{\mathbf{4}}}{{\mathbf{C}}_{\mathbf{3}}} + {\text{ }}{{\mathbf{H}}_{\mathbf{2}}}{\mathbf{O}} \to {\mathbf{C}}{{\mathbf{H}}_{\mathbf{4}}}$
B. $\;\;\;{\mathbf{CaC2}}{\text{ }} + {\text{ }}{{\mathbf{H}}_{\mathbf{2}}}{\mathbf{O}}\; \to \;{{\mathbf{C}}_{\mathbf{2}}}{{\mathbf{H}}_{\mathbf{2}}}$
C. $\;\;\;{\mathbf{M}}{{\mathbf{g}}_{\mathbf{2}}}{{\mathbf{C}}_{\mathbf{3}}} + {\text{ }}{{\mathbf{H}}_{\mathbf{2}}}{\mathbf{O}}\; \to {\mathbf{C}}{{\mathbf{H}}_{\mathbf{3}}}{\mathbf{C}} \equiv {\mathbf{CH}}$
D. $\;\;{\mathbf{M}}{{\mathbf{e}}_{\mathbf{3}}}{\mathbf{C}}-{\mathbf{H}}{\text{ }} + {\text{ }}{\mathbf{KMn}}{{\mathbf{O}}_{\mathbf{4}}}\; \to {\mathbf{M}}{{\mathbf{e}}_{\mathbf{3}}}{\mathbf{C}}-{\mathbf{OH}}$

Answer 1

In the given question we have given the different chemical reactions and their products, we have to rectify all the reactions and state which of the reactions is correct. Correct reaction can be identified by their products formed within.

Complete Step by step answer: When we react Aluminium carbide with water it gives methane and byproducts. As Aluminium carbide is used in the preparation of methane. ​ The reaction occurs is –
So, $A{l_4}{C_3} + {\text{ }}{H_2}O\; \to Al{\text{ }}{\left( {OH} \right)_3} + {\text{ }}3C{H_4} + 4A{l^{3 + }} + {\text{ }}3{C^{4-}}$
Hence, option A is the correct answer.
When we treat Calcium carbide with water it gives calcium hydroxide and a byproduct. Also, Calcium carbide is used in the preparation of acetylene. The reaction occurs is -
$C{a^{2 + }}^-C \equiv {C^-} + {\text{ }}{H_2}O \to Ca{\text{ }}{\left( {OH} \right)_2} + {\text{ }}HC \equiv CH$
Hence, option B is correct.
When we treat Magnesium carbide with water it gives a triple bond product and by product. Magnesium carbide is used in the preparation of propyne. ​The reaction occurs is -
$2M{g^{2 + }} + {\text{ }}{C_3}^{4-} + {\text{ }}{H_2}O \to Mg{\text{ }}{\left( {OH} \right)_2} + {\text{ }}{H_3}C-C \equiv CH + {{\text{ }}^{3-}}C-C \equiv {C^-}$
Hence, option C is correct.
When we treat reaction in presence of acidified potassium permanganate solution, tert butane is oxidized to tert butanol thus it is the product obtained. The reaction occurs is -
$M{e_3}C-H + KMn{O_4} \to M{e_3}C-OH\;$

Hence, option D is the correct answer.

Therefore, in the given question all of the above reactions are correct. Thus, all are correct options.

Note: calcium carbide used in the manufacture of acetylene gas, potassium permanganate is an oxidizing agent and has astringent properties, Aluminum carbide is used as a rasping in high-speed cutting tools, Magnesium Carbide is accessible in frequent forms and convention shapes including discs, rods, sputtering targets.