Question

Which has maximum number of atoms?

• A. 24 g of C (12)
• B. 56 g of Fe (56)
• C. 27 g of A1 (27)
• D. 108 g of Ag (108)

Answer 1

Answer: (A)

24 g of C (12)

Answer 2

The correct answer is A:24g of C(12)
Number of atoms = Number of moles
$\times$ Avogadro's number $(N_A)$
Number of atoms in 24 g C = $\frac{ 24}{12} \times N_A = 2N_A$
Number of atoms in 56 g of Fe = $\frac{ 56}{56}N_A = N_A$
Number of atoms in 27 g of Al = $\frac{27}{27}N_A = N_A$
Number of atoms in 108 g of Ag = $\frac{108}{108} N_A = N_A$
Hence, 24 g of carbon has the maximum number of atoms.