Question

Which halogen forms an oxyacid that contains the halogen atom in tripositive oxidation state?
A.Fluorine
B.Chlorine
C.Bromine
D.Iodine

Answer 1

If the acid has oxygen (called an oxoacid), then the suffixes –ous and –ic is used , representing the lower and higher number of oxygens in the acid formula. Oxoacids have hydrogen, oxygen, and other element Acids that contain hydrogen, oxygen, and another element are called oxoacids.
Group 17 contains fluorine, chlorine, bromine, iodine, and astatine. They are known as halogens, meaning salt producers.
Halogens have small size due to their effective nuclear charge.
Hence, they can not lose electrons, so they easily gain an electron to complete their octet.
The central atom in the oxoacids is $s{p^3}$ hybridized. Every oxoacid has essentially one $X - OH$ bond. Whereas most oxoacids have $X = O$ bonds present in them. This double bond between oxygen and halogen is d π-π in nature.

Complete step by step answer:
Chlorine halogen forms an oxyacid that contains the halogen atom in a tripositive oxidation state, the oxyacid of $Cl$ is $HCl{O_2}$ ​. In $HCl{O_2}$ ​, the oxidation number of chlorine is +3.
In the case of chlorine, the oxyacid that contains the halogen atom in tripositive oxidation state.
Therefore, the correct option is B.

Note:
Properties of Halogen Oxoacids
Halogens generally form four series of oxoacids namely hypohalous acids (+1 oxidation state), halous acids (+3 oxidation state), halic acids (+5 oxidation state) and perhalic acids (+7 oxidation state).
Chlorine forms four types of oxoacids. That is $HOCl$(hypochlorous acid),$HOClO$ (chlorous acid), $HOCl{O_2}$(chloric acid) and lastly $HOCl{O_3}$(perchloric acid).
Bromine forms $HOBr$ (hypobromous acid), $HOBr{O_2}$ (bromic acid) a $HOBr{O_3}$ (perbromic acid). Iodine forms $HOI$ (hypoiodous acid), $HOI{O_2}$ (iodic acid) and $HOI{O_3}$ (periodic acid).