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Question

Question: Which ellipse lies completely inside \|\(\sqrt{3}\)x \| + \| \(\sqrt{6}\) y\| = \(\sqrt{18}\)...

Which ellipse lies completely inside

|3\sqrt{3}x | + | 6\sqrt{6} y| = 18\sqrt{18}

A

x26+y23=1\frac{x^{2}}{6} + \frac{y^{2}}{3} = 1

B

x25+y22=1\frac{x^{2}}{5} + \frac{y^{2}}{2} = 1

C

x26+y22=1\frac{x^{2}}{6} + \frac{y^{2}}{2} = 1

D

x28+y22=1\frac{x^{2}}{8} + \frac{y^{2}}{2} = 1

Answer

x25+y22=1\frac{x^{2}}{5} + \frac{y^{2}}{2} = 1

Explanation

Solution

Sol. \ if x > 0, y > 0, given equation become

3x+6y=18\sqrt{3}x + \sqrt{6}y = \sqrt{18}

x6+y3\frac{x}{\sqrt{6}} + \frac{y}{\sqrt{3}} = 1

Similarly taking all condition.

The graph is as shown in figure.