Question

Which element has the electron configuration of $1{s^2}2{s^2}2{p^6}3{s^2}3{p^6}4{s^2}3{d^3}$ ?

Answer 1

The chemical elements are arranged in the modern periodic table in the increasing order of atomic number. Atomic number gives the number of protons which is equal to the number of electrons. when the last electron enters into d-orbital then that element belongs to d-block. Vanadium is the element with atomic number $23$ has the five valence electrons. out of which three electrons are in d-orbital.

Complete answer:
Periodic table is the representation of chemical elements arranged in the increasing order of atomic numbers in vertical columns and horizontal rows. The vertical columns were known as groups and the horizontal rows were known as periods. There are a total of $118$ elements arranged in $7$ periods and $18$ groups. These elements are also divided into four blocks namely s, p, d, and f blocks. The elements whose last electron is entering into d-orbital are known as d-block elements.
The d-block elements have three series namely $3d,4d,$ and $5d$ series. Vanadium is the element with atomic number $23$ belongs to $3d$ series. It has $23$ electrons arranged in the orbitals according to their energy. The electronic configuration of vanadium is $1{s^2}2{s^2}2{p^6}3{s^2}3{p^6}4{s^2}3{d^3}$ , which has five valence electrons.
Thus, the element has the electron configuration of $1{s^2}2{s^2}2{p^6}3{s^2}3{p^6}4{s^2}3{d^3}$ is vanadium.

Note:
Vanadium is the element that belongs to $3d$ series in d-block, as the last electron is entering into $3d$ orbital. It has the chemical symbol of V. Vanadium can be used in medicine supplements to treat many diseases like tuberculosis, diabetes, low blood sugar and high cholesterol.