Question

Which compound among the following has lowest oxidation number of chlorine?

• A. $HClO_{4}$
• B. $HClO_{3}$
• C. HCl
• D. HOCl

Answer 1

Answer: (C)

HCl

Answer 2

: HCl : 1 + x = 0 $\Rightarrow$x = - 1

$HClO_{4}:1 + x - 8 = 0 \Rightarrow x = + 7$

$HClO_{3}:1 + x - 6 = 0 \Rightarrow x = + 5$

HOCl: 1 – 2 + x = 0 $\Rightarrow$ x = + 1