Question

Which cell will measure standard electrode potential of copper electrode?

• A. $Pt_{(s)}|H_{2}(g,0.1bar)|H^{+}(aq,1M)||Cu^{2 +}(aq,1M)|Cu$
• B. $Pt_{(s)}|H_{2}(g,1bar)|H^{+}(aq,1M)||Cu^{2 +}(aq,2M)|Cu$
• C. $Pt_{(s)}|H_{2}(g,1bar)|H^{+}(aq,1M)||Cu^{2 +}(aq,1M)|Cu$
• D. $Pt_{(s)}|H_{2}(g,1bar)|H^{+}(aq,0.1M)||Cu^{2 +}(aq,1M)|Cu$

Answer 1

Answer: (C)

$Pt_{(s)}|H_{2}(g,1bar)|H^{+}(aq,1M)||Cu^{2 +}(aq,1M)|Cu$

Answer 2

$Pt_{(s)}|H_{2}(g,1bar)|H^{+}(aq,1M)||Cu^{2 +}(aq;1M)|Cu$ will measure standard electrode potential of the given copper electrode.

To calculate the standard electrode potential of the given cell it is coupled with standard hydrogen electrode in which pressure of hydrogen gas is one bar and the conc. Of $H^{+}$ion in the solution is one molar and also the concentration of the oxidized and the reduce3d forms of the species in the right hand half cell are unity.