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Question: Which arrangement of 3\(2 \times 10^{- 2}\Omega\) resistors will given a total resistance of 7 \(15\...

Which arrangement of 32×102Ω2 \times 10^{- 2}\Omega resistors will given a total resistance of 7 15Ω15\Omega?

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Answer
Explanation

Solution

: Three resistors of 3Ω3\Omega each in parallel will give

(113+13+13)=1Ω\left( \frac{1}{\frac{1}{3} + \frac{1}{3} + \frac{1}{3}} \right) = 1\Omega

Req=3+1+3=7ΩR_{eq} = 3 + 1 + 3 = 7\Omega