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Question: Which among the following is a function of tRNA? A. Production of mRNA B. Production of ribosome...

Which among the following is a function of tRNA?
A. Production of mRNA
B. Production of ribosome
C. Production of microsome
D. Selection of amino acids

Explanation

Solution

Hint:- Ribonucleic acid-RNA, which consists predominantly of nucleic acids, is involved in a range of cell functions and is present in all living organisms, including viruses, bacteria, plants, and animals. This nucleic acid acts in cell organelles as a structural molecule and is also engaged in the catalysis of biochemical reactions.

Complete answer:-
t-RNA (transfer RNA) is responsible for selecting the right protein or the amino acids that the body requires to sustain the ribosomes in-turn. It is located at each of the amino acid endpoints. This is also referred to as soluble RNA, and a connection between the messenger RNA and the amino acid is formed.
rRNA (Ribosomal RNA) is the ribosome portion and is located inside a cell's cytoplasm, where ribosomes are contained. Ribosomal RNA plays a central role in the synthesis and translation of mRNA into proteins in all living cells. RRNA consists primarily of cellular RNA and is the most prevalent RNA in the cells of all living beings.
mRNA (Messenger RNA) is a type of RNA that works by passing the genetic material into the ribosomes and transmitting the protein-type instructions needed by the cells of the body. Depending on the functions, the messenger RNA has termed these types of RNA. The mRNA thus plays a crucial role in the transcription process or during the process of protein synthesis.
Thus, the right option is D.

Note:- With just 2 primary variations inside it, the ribonucleic acid has all the components equal to that of the DNA. Except for the Thymine that is substituted by the uracil, RNA has the same nitrogen bases called adenine, Guanine, Cytosine as that of DNA. Adenine and uracil are known to be the key building blocks of RNA and, with the aid of 2 hydrogen bonds, both form base pairs.