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Physics Question on Electromagnetic waves

Which among the following does not represent Maxwell's equation?

A

∮E⃗.dA→=qε0\oint\vec{E}.\overrightarrow{dA} = \frac{q}{\varepsilon_{0}}

B

∮B⃗.dA→=0\oint\vec{B}.\overrightarrow{dA} = 0

C

∮ E⃗.dl→ = −dBdt\oint \:\vec{E}.\overrightarrow{dl}\:=\:\frac{-dB}{dt}

D

∮B⃗.dl→=μ0IC+μ0ε0dϕEdt\oint \vec{B}.\overrightarrow{dl} = \mu_{0}I_{C} + \mu_{0}\varepsilon_{0}\frac{d\phi_{E}}{dt}

Answer

∮ E⃗.dl→ = −dBdt\oint \:\vec{E}.\overrightarrow{dl}\:=\:\frac{-dB}{dt}

Explanation

Solution

Maxwell's equations are as follows (i) ∮E⃗.dA→=qε0\oint\vec{E}.\overrightarrow{dA} = \frac{q}{\varepsilon_{0}} (Gauss?s law of electricity) (ii) ∮B⃗.dA→=0\oint\vec{B}.\overrightarrow{dA} = 0 (Gauss?s law of magnetism) (iii) ∮E⃗.dl→=−dϕEdt\oint \vec{E}.\overrightarrow{dl} = -\frac{d\phi_{E}}{dt} (Faraday?s law) (iv) ∮B⃗.dl→=μ0IC+μ0ε0dϕEdt\oint \vec{B}.\overrightarrow{dl} = \mu_{0}I_{C} + \mu_{0}\varepsilon_{0}\frac{d\phi_{E}}{dt} (Ampere - Maxwell law)