Question

Which among the following does not represent Maxwell’s equation?

• A. $\oint_{}^{}{\overrightarrow{E}.\overset{\rightarrow}{dA} = \frac{q}{\varepsilon_{0}}}$
• B. $\oint_{}^{}{\overrightarrow{B}.d\overrightarrow{A} = 0}$
• C. $\oint_{}^{}{\overrightarrow{E}.d\overrightarrow{l} = \frac{- dB}{dt}}$
• D. $\oint_{}^{}{\overrightarrow{B}.d\overrightarrow{l} = \mu_{0}I_{C} + \mu_{0}\varepsilon_{0}\frac{d\varphi_{E}}{dt}}$

Answer 1

Answer: (C)

$\oint_{}^{}{\overrightarrow{E}.d\overrightarrow{l} = \frac{- dB}{dt}}$

Answer 2

: Maxwell’s equations are as follows

(i) $\oint_{}^{}{\overrightarrow{E}.\overset{\overset{\quad\quad}{\rightarrow}}{dA} = \frac{q}{\varepsilon_{0}}}$ (Gauss’s law of electricity)

(ii) $\oint \overrightarrow { \mathrm { E } } \cdot \overrightarrow { \mathrm { dA } } = 0$ (Gauss’s law of magnetism)

(iii) $\oint_{}^{}{\overrightarrow{E}.\overset{\overset{\quad\quad}{\rightarrow}}{dA} = \frac{d\varphi}{dt}}$ (Faraday’s law)

(iv) $\oint_{}^{}{\overrightarrow{B}.\overset{\overset{\quad\quad}{\rightarrow}}{dt} = \mu_{0}\varepsilon_{0}\frac{d\varphi_{E}}{dt}}$ (Ampere – Maxwell law)