Question

Which among the following compounds will have meso form

• A. $CH_2OH - CHOH - CHOH - CHO$
• B. $CH_2OH - CHOH - CHOH - COOH$
• C. $CH_2OH - (CHOH)_2 - CH_2OH$
• D. $C_6H_3 - CHCl - CHOH - CH_3$

Answer 1

Answer: (C)

$CH_2OH - (CHOH)_2 - CH_2OH$

Answer 2

$CH_2OH? CHOH? CHOH? COOH$

will have meso form.

The structures that have plane of symmetry, which can divide it into two equal and identical

halves are called meso structures.

In the given compounds, only structure (b) has plane of symmetry, hence it is a meso compound.

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