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Question: Which among the following are intramolecular redox reactions? The question has multiple correct an...

Which among the following are intramolecular redox reactions?
The question has multiple correct answer
A. PCl5PCl3 + Cl2{\text{PC}}{{\text{l}}_{\text{5}}} \to {\text{PC}}{{\text{l}}_{\text{3}}}{\text{ + C}}{{\text{l}}_{\text{2}}}
B. CHO - CHO + OH  COO -  - CH2OH{\text{CHO - CHO + }}{\text{OH }} \to {\text{ CO}}{{\text{O}}^{\text{ - }}}{\text{ - C}}{{\text{H}}_{\text{2}}}{\text{OH}}
C. 2KClO32KCl + 3O2{\text{2KCl}}{{\text{O}}_{\text{3}}} \to {\text{2KCl + 3}}{{\text{O}}_{\text{2}}}
D. NH4NO2 N2 + 2H2O{\text{N}}{{\text{H}}_{\text{4}}}{\text{N}}{{\text{O}}_{\text{2}}} \to {\text{ }}{{\text{N}}_{\text{2}}}{\text{ + 2}}{{\text{H}}_{\text{2}}}{\text{O}}

Explanation

Solution

Check for both the oxidation and reduction reaction in these reactions. Also look for the species which are undergoing the oxidation and reduction for finding the answer.

Complete step by step answer:
The phosphorus pentachloride is being decomposed and such reaction is an intramolecular redox reaction. As for the reason, the oxidation state phosphorus of PCl5PC{l_5} is +5 + 5 and is changed to +3 + 3 when it converts to PCl3PC{l_3}. Similarly the oxidation state of ClCl in PCl5PC{l_5} is 1 - 1 and is changed to 00 in Cl2C{l_2}. Hence, the reaction is an Intramolecular redox reaction.
In case 2,
One aldehyde group (CHO)\left( { - CHO} \right) is oxidized to carboxylic group (COO)\left( {CO{O^ - }} \right) whereas other aldehyde group is reduced to alcohol group (OH)\left( {OH} \right). Hence this reaction is also an Intramolecular redox reaction.
In case 3,
The oxidation number of Chlorine in KClO3KCl{O_3} is changing from +5 + 5 to 1 - 1 in KClKCl, means Chlorine is being reduced. Similarly the oxidation number of oxygen is changing from 2 - 2 in KClO3KCl{O_3} to 1 - 1 in O3{O_3} which means Oxygen is oxidized. Hence, this reaction is also an Intramolecular redox reaction.
In case 4,
The oxidation number of nitrogen in ammonia is changing from 3 - 3 to 00 in N2{N_2} which indicates that nitrogen is undergoing oxidation. Similarly, the oxidation number of nitrogen in NO2N{O_2} is changing from +4 + 4 to 00 in N2{N_2} which means it is undergoing reduction. Hence this reaction is also an Intramolecular redox reaction.
Hence,

\therefore The answer to this question is option A, B, C, D.

Note:
Intramolecular Redox reactions are the reactions in which a single molecule is undergoing both the oxidative and reductive changes. You can consider all the above reactions as an example of such. It is to be noted that most of the redox reactions are intermolecular and not intramolecular.