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Question: When two mole of an ideal gas \(\left( C_{p,m} = \frac{5}{2}R \right)\) heated from 300 K to 600 K a...

When two mole of an ideal gas (Cp,m=52R)\left( C_{p,m} = \frac{5}{2}R \right) heated from 300 K to 600 K at constant pressure. The change in entropy of gas (Δ\DeltaS) is :

A

32\frac{3}{2}R ln 2

B

–R32\frac{3}{2}ln 2

C

5R ln 2

D

52\frac{5}{2}R ln 2

Answer

5R ln 2

Explanation

Solution

Δ\DeltaS = nCp, m In T2T1\frac{T_{2}}{T_{1}} = 2 × 52\frac{5}{2}R In 600300\frac{600}{300} = 5 R In 2