Question

When three dice are thrown the probability of getting a $4$ or $5$ so on each of the dice simultaneously is

• A. $\frac{1}{72}$
• B. $\frac{1}{108}$
• C. $\frac{1}{24}$
• D. None of these

Answer 1

Answer: (D)

None of these

Answer 2

Total number of cases $={{6}^{3}}=216$
Favourable cases are $445,454,544,455,545,$
$554,555,444.$ $\therefore$
Total number of favourable cases $=8$
$\therefore$ Required probability $=\frac{8}{216}=\frac{1}{27}$