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Question: When the voltage drop across a p – n junction dodeis increased from \(0.65\) V to \(0.70V,\) the cha...

When the voltage drop across a p – n junction dodeis increased from 0.650.65 V to 0.70V,0.70V, the change in the diode current is 5 mA. The dynamic resistance of the diode is.

A

20Ω20\Omega

B

50Ω50\Omega

C

10Ω10\Omega

D

80Ω80\Omega

Answer

10Ω10\Omega

Explanation

Solution

: Dynamic resistance, rd=ΔVΔIr_{d} = \frac{\Delta V}{\Delta I}

rd=0.7V0.65V5×103A=0.05×10005Ω=10Ωr_{d} = \frac{0.7V - 0.65V}{5 \times 10^{- 3}A} = \frac{0.05 \times 1000}{5}\Omega = 10\Omega