Question

When the voltage drop across a p – n junction diode is increased from $0.65$ V to $0.70V,$ the change in the diode current is $5mA.$ The dynamic resistance of the diode is

• A. $5\Omega$
• B. $10\Omega$
• C. $20\Omega$
• D. $25\Omega$

Answer 1

Answer: (B)

$10\Omega$

Answer 2

: Dynamic resistance is

$r_{rd} = \frac{\Delta V}{\Delta I}$

Here, $\Delta V = 0.7 - 0.65V = 0.05V$

$\Delta I = 5mA = 5 \times 10^{- 3.}A$

$\therefore r_{d} = \frac{0.05}{5 \times 10^{- 3}} = 10\Omega$