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Question: When the temperature of an iron sphere of \(1kg\) falls from \({30^0}C\) to \({25^0}C\), \(550\) cal...

When the temperature of an iron sphere of 1kg1kg falls from 300C{30^0}C to 250C{25^0}C, 550550 calories of heat is released. The heat capacity of iron sphere in Cal/0CCal{/^0}C is
A)110110
B)220220
C)330330
D)440440

Explanation

Solution

Hint: We can use the formula to find the heat required to change the temperature of a body when temperature difference is given. The formula is given by H=mSΔTH = mS\Delta T
Where,
mm is mass of the block,
SSis specific heat of the block,
ΔT\Delta T is a change in temperature.

Complete step by step answer:
It is the property of a body that the heat required to raise the temperature of a body byΔT\Delta Tis exactly the same as the heat lost by the body when its temperature decreases by the same ΔT\Delta T.
H=mSΔTH = mS\Delta T
550=S(3025)550 = S(30 - 25)
550=S×5550 = S \times 5
Cp=110Cal/0C{C_p} = 110Cal{/^0}C
A) is correct.

Additional information:
The specific heat capacity of a substance is the heat capacity of a sample of the substance divided by the mass of the sample. Informally, it is the amount of energy that must be added, in the form of heat, to one unit of mass of the substance in order to cause an increase of one unit in its temperature.
The specific heat often varies with temperature, and is different for each state of matter. Liquid water has one of the highest specific heats among common substances.

Note: Specific heat varies with the change in temperature. In this question, the change in temperature is very small so we can take the specific heat capacity to be constant.