Question

When the same amount of electricity is passed through solutions of silver nitrate and copper sulphate, 0.4 g copper is deposited. The amount of silver deposited is

• A. 1.35 g
• B. 2.7 g
• C. 5.1 g
• D. 5.4 g

Answer 1

Answer: (A)

1.35 g

Answer 2

According to Faraday's second law of electrolysis,
$\frac{w_{1}}{w_{2}} = \frac{E_{1}}{E_{2}}$
$w_{2} = \frac{w_{1 } \times E_{2}}{E_{1}} = \frac{0.4 \times 107.8}{63.5 2} = 1.35 g$