Question

When the same amount of Al is treated with an excess of $HCl$ and $NaOH$ , the volumes of hydrogen evolved are in the ratio of:

• A. 1:01
• B. 2:03
• C. 1:02
• D. 2:01

Answer 1

Answer: (A)

1:01

Answer 2

Aluminium reacts with $HCl$ and NaOH, as follows: $2Al+6HCl\xrightarrow{{}}2AlC{{l}_{3}}+3{{H}_{2}}\uparrow$ $2Al+2NaOH+2{{H}_{2}}O\xrightarrow{{}}2NaAl{{O}_{2}}+3{{H}_{2}}\uparrow$ Hence, ratio of hydrogen evolved in both cases is 1 : 1.