Question

When the radioactive isotope $_{88}Ra^{226}$ decays in a series by emission of three alpha $(α)$ and a beta $(β)$ particle, the isotope $X$ which remains undecay is

• A. $_{83}X^{214}$
• B. $_{84}X^{218}$
• C. $_{84}X^{220}$
• D. $_{87}X^{223}$

Answer 1

Answer: (A)

$_{83}X^{214}$

Answer 2

The correct option is (A): $_{83}X^{214}$.